.00012=x^2

Solution for .00012=x^2 equation:

.00012=x^2

We move all terms to the left:

.00012-(x^2)=0

We add all the numbers together, and all the variables

-1x^2+0.00012=0

a = -1; b = 0; c = +0.00012;
Δ = b2-4ac
Δ = 02-4·(-1)·0.00012
Δ = 0.00048
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{0.00048}}{2*-1}=\frac{0-\sqrt{0.00048}}{-2}
=-\frac{\sqrt{}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{0.00048}}{2*-1}=\frac{0+\sqrt{0.00048}}{-2}
=\frac{\sqrt{}}{-2}
$